[{"data":1,"prerenderedAt":62},["ShallowReactive",2],{"q-110180-arch_structure-32":3},{"question":4,"neighbors":27,"sameNumber":46,"prev":35,"next":38},{"id":5,"classKey":6,"session":7,"year":8,"subject":9,"number":10,"groupStem":11,"ownStem":12,"stem":12,"options":13,"answer":18,"answerKind":20,"answerS":11,"answerNote":11,"images":21,"explanation":23,"withheld":11,"deepChars":24,"freq":25,"indexable":26},"arch-110180-801-0102-032","architect","110180",110,"建築結構",32,null,"圖示桁架結構在 F、E 點受力分別為 P1 = 10 kN 及 P2 = 15 kN，下列關於桿件受力大小的敘述何者錯誤？ 4m 2m 4m 2m P1 P2",{"A":14,"B":15,"C":16,"D":17},"FBC = 15 kN","FCD = 0 kN","FEC = 15 kN","FBF = 20 kN",[19],"D","single",[22],"\u002Fimages\u002Farch-110180-801-0102-032.png","本題考點：桁架節點法——從未知桿力最少的自由端節點開始，依序解 D、E、C、F 四個節點，並善用零桿判別與 45° 斜桿水平、垂直分量相等的特性。\n【正解理由】依題圖所示，F、E、D 位於下弦，B、C 位於上弦，桁架高 4 m；F 到 E 水平距離 4 m，所以斜桿 FC 水平與垂直投影都是 4 m，傾角 45°。D 點：只連接斜桿 CD 與水平桿 DE，無外力也無支承，垂直方向只有 CD 有分量，CD = 0，進而 DE = 0。E 點：DE 為零，剩水平桿 EF 與豎桿 EC，垂直平衡得 EC = 15 kN（拉力），水平平衡得 EF = 0。C 點：EC 以 15 kN 向下拉 C 點，CD 為零，垂直方向只能由 CF 平衡，CF 的垂直分量為 15 kN（CF 受壓），45° 斜桿的水平分量也是 15 × 4 \u002F 4 = 15 kN，水平平衡得 BC = 15 kN（拉力）。F 點：CF 受壓，對 F 點施加向下 15 kN 的垂直分量，再加上 P1 = 10 kN 向下，豎桿 BF 須提供 15 + 10 = 25 kN 向上，BF = 25 kN（拉力），不是 20 kN。故選 D。\n【逐項排除】\n(A) 敘述正確。C 點水平平衡：CF 的水平分量 15 kN 由上弦 BC 平衡，BC = 15 kN（拉力）。\n(B) 敘述正確。D 點只連接 CD 與 DE 且無外力，CD 的垂直分量無從平衡，CD = 0，DE 也隨之為零。\n(C) 敘述正確。E 點 DE、EF 皆為水平且無垂直分量，P2 = 15 kN 全由豎桿 EC 承受，EC = 15 kN（拉力）。\n(D) 敘述錯誤。F 點垂直平衡要同時承擔 P1 = 10 kN 與斜桿 CF 傳來的 15 kN 垂直分量，BF = 25 kN；只要漏掉其中任一項，數值就會與正確值不符。\n【演算步驟】\nD 點：ΣFy = 0 → FCD 垂直分量 = 0 → FCD = 0 kN；ΣFx = 0 → FDE = 0 kN\nE 點：ΣFy = 0 → FEC = P2 = 15 + 0 = 15 kN（拉）；ΣFx = 0 → FEF = 0 kN\nC 點：ΣFy = 0 → FCF 垂直分量 = 15 kN（壓）；FCF 水平分量 = 15 kN × 4 m \u002F 4 m = 15 kN；ΣFx = 0 → FBC = 15 kN（拉）\nF 點：ΣFy = 0 → FBF = 15 kN + 10 kN = 25 kN（拉）\n【記憶點】節點法從「兩根桿、無外力」的自由端開始解；45° 斜桿的水平分量等於垂直分量。",550,1,true,[28,31,34,37,40,43],{"number":29,"session":7,"stem":30},29,"我國交通部中央氣象局於 109 年施行新的地震震度分級制度，讓地震震度分布與災害位置…",{"number":32,"session":7,"stem":33},30,"無梁版系統在我國較少應用於上部結構，大多僅應用在地下室結構，下列敘述何者錯誤？",{"number":35,"session":7,"stem":36},31,"原有一剛構架進行耐震補強，在兩側增設圖示之桿件，其中 A、D 為固端，B、C 為鉸接…",{"number":38,"session":7,"stem":39},33,"有一簡支梁承受均布載重如圖所示，若梁自重不計，下列何者所得之最大正彎矩值與此梁相同？",{"number":41,"session":7,"stem":42},34,"圖中構架 ABCD 之 A 點固端彎矩為何？ 3m 2 kN 4m 10 kN-m …",{"number":44,"session":7,"stem":45},35,"下圖的結構中，關於支承 A、B 點之反力的敘述何者錯誤？ 60°",[47,50,53,56,59],{"number":10,"session":48,"stem":49},"114180","耐震設計時為了確保鋼筋混凝土結構之韌性行為，下列敘述何者錯誤？",{"number":10,"session":51,"stem":52},"113190","下列何者有助於提升鋼筋混凝土結構韌性？",{"number":10,"session":54,"stem":55},"112190","下列何者不屬於鋼造梁構件可能之破壞模式？",{"number":10,"session":57,"stem":58},"111180","下列那一項不是橫向閉合箍筋在鋼筋混凝土柱中的作用？",{"number":10,"session":60,"stem":61},"109180","如圖示之剛構架，AB、BC、CD 之長度均為 L 且為相同斷面，EI = 撓曲剛度，…",1791863205092]